4.7+due+10-22

2a. arccos(1/2) = pi/3 b. arccos(0)= pi/2 4a. cos-1 (-sqrt[2]/2)= 3pi/4 b. sin-1 (-sqrt[2]/2)= -pi/4 6a. arccos(-1/2)= 2pi/3 b. arcsin(sqrt[2]/2)= pi/4 Done by Rachel West

12. (1st ordered pair starting from top of graph) (2nd ordered pair) (3rd ordered pair) y=arccosx pi/6=arccosx y=arccosx y=arccos(-1/2) x=√3/2 y=arccos(-1) y=2pi/3 y=pi

14. arcsin(.56) = .59 Done by:Valeria Chelala

I agree with Valeria! -blake schreiber Done by Aggie Tutia

32. tan(arctan35) = 35 34. sin[acsin(-.1)]

By Alyssa Johnson I got the same answers! Checked by:Amy Finkelstein



36 & 38 Done by Mady Smith I got the same for 36 & 38. Checked by: Meredith Hohl

Sorry I had a show but if you need it here is my solution with the triangles Done by: Leslie Baker

40. sec(arcsin(3/5))= 5/4 42. csc[arctan(-12/5)] = -13/12 Done by: Jennifer Hassell (I was supposed to check, but no one has done these yet)

48-50) Done by Jonathan Eichelberger

I got the same thing for 48, and on 50 I got 1/x^2-2x-1, but you're probably right.

44 & 46) Done by: Emma McRae I agree with Emma! Checked By: Frances Dannenbrink

52 & 54 Done by Morgan Miller

52&54 looks great, I agree with Morgan! checked by Kelsey Harmon


 * 56

First I set the equations equal to each other. Then using inverse cos x/2, I made a reference triangle. I then used the reference triangle to find the tan of the first equation, which ended up making the equations equal

Done by: Miles Hennington

Lookin' good! I got the same answers. Checked By: Courtney Venable

Done By: Alyssa Sturgis 86. A)tan^(-1)0= 0 tan^(-1)1=pi/4 pi/4-0= pi/4 B) tan^(-1)0=0 tan^(-1)3=1.249 1.249-0 = 1.249 C)tan^(-1)-1= -pi/4 tan^(-1)1=pi/4 pi/4-(-pi/4)= pi/2 D)tan^(-1)-1=-pi/4 tan^(-1)3=1.249 1.249-(-pi/4)= 2.034 Done by Alex Dubois- was not really sure what the arctan of 3 becomes so i plugged it into the calc

For A, C, and D I got the same answers. I wasn't sure how to do arctan3 either (whether the you had to break it up using the identities, or if they even worked for the inverses) so I too plugged it into my calculator and received the same answers. For B however I got: Area=arctana-arctanb (when a=-1 and b=1) Area= arctan(1)-arctan(0) Area= (pi/4)-(-pi/4) Area= 2pi/4 Area=pi/2 Checked by Emily Johnson