8.4+(day+1)+due+2-7

Done by Gretchen Schneider I got the same thing! Good job, Gretchen! - Clarissa Rodriguez
 * 2, 4, 6

done by: Rebekah Adair 10) I agree- Valerie Finstad  righteous! roflcopter!!!!!

10)


 * 1) 10 done by Frances Dannenbrink

Looks good Frances, I got the same thing. Checked by Cameron Johnson

12. 2(1+3+3^2+3^3+...+3^(n-1) = (3^n) - 1 Step 1:S(1) let n = 1 2(3^1-1) = (3^1) - 1 2(3^0) = 3-1 2(1) = 2 2=2 Step 2: let n=k & assume true 2(1+3+3^2+3^3+...+3^(k-1)) = (3^k) - 1 Step 3: Prove S(k+1) 2(1+3+3^2+3^3+...3^k-1+3^(k-1+1) = (3^k+1)-1 (3^k)-1 + [2(3^k) = 3^(k+1) - 1 (3^k) +2(3^k) -1 = 3^(k+1) - 1 3^(k+1)-1 = 3^(k+1) - 1 Step 4: since S(1_ is true S(k) -> S(k+1) is true, then the statement is true for all integers n greater or equal to 1
 * 1) 12 by Alex Dubois

checked by : Andrew Kim
 * 1) 12 looks good to me

Looks great Checked by Meredith Hohl
 * 1) 14 done by Kamryn Richard

done by: Morgan Miller

I agree. -Heather Henry