4.3+due+9-2


 * __REMINDER:__ Problems need to be in numerical order and at the end of each section the name of the person who worked the problems and the person who checked the problems needs to be listed.**

2) x^2 + 5^2 = 13^2 x^2 + 25 = 169 - 25 = -25 x^2 = 144 x = 12

sin θ = opposite/hypotenuse=5/13 csc θ = 13/5 cos θ = adjacent/hypotenuse=12/13 sec θ = 13/12 tan θ = opposite/adjacent=5/12 cot θ = 12/5

Done: by: Mady Smith Cannot "edit" wiki, but can see the wiki. She said she got the same answers.Checked by Alyssa Sturgis   4. check by Jan Dudek (The problem wasn't here so I'll just write my results) sin=9 x sqrt13/39  csc=sqrt13/3 cos=6 x sqrt13/39 sec=6 x sqrt13/12 tan=18/39 cot=39/18 <span style="font-family: sans-serif,helvetica,sans-serif;">** cos x = **** (2√13)/13 ** <span style="font-family: sans-serif,helvetica,sans-serif;">** sec x = **** (√13)/2 ** <span style="font-family: sans-serif,helvetica,sans-serif;">** tan x = 3/2 ** <span style="font-family: sans-serif,helvetica,sans-serif;">** cot x = 2/3 **
 * CORRECTION: **
 * sin x = **<span style="font-family: sans-serif,helvetica,sans-serif;">** (3√13)/13 **

<span style="display: block; font-family: sans-serif,helvetica,sans-serif; margin: 0px; padding: 0px;"> <span style="display: block; font-family: sans-serif,helvetica,sans-serif; margin: 0px; padding: 0px;"><span style="font-family: sans-serif,helvetica,sans-serif;">6. <span style="display: block; font-family: sans-serif,helvetica,sans-serif; margin: 0px; padding: 0px;"><span style="font-family: sans-serif,helvetica,sans-serif;"> <span style="display: block; font-family: sans-serif,helvetica,sans-serif; margin: 0px; padding: 0px;"><span style="font-family: sans-serif,helvetica,sans-serif;">done by Cameron Johnson I got the same thing. Nice job! Checked by: Michael MacCrory

Done by: Alyssa Johnson I got the same amswers the same way. Checked by Matthew Milan :D->-<

Got the same answers. Will Duffy


 * 1) 14. Done by Miles Hennington
 * 2) 14 checked by Peter Radecki for the tan i got 4root273 over 273 and for cot i got root273 over 4

Done by Gretchen Schneider I didn't get D either and i got the same answers for the others. checked by Andrew Kim
 * CORRECTION: #30 **
 * d) sinx = (2 **** √6)/5 **

b: cos beta b =1
 * 1) 32 a: cot of beta B =1/5

c: tan(90-beta B)=0

d: csc of beta B =1/5 done by Kristen Hanslik
 * CORRECTION: #32 use the identities to help you!!! **


 * a) cotβ = 1/5 **
 * b) cosβ = 1/(secβ) **
 * 1 + tan²β = sec²β **
 * 1+ 25 = sec²β **
 * ±√26 = sec²β **
 * Cosβ = ±(√26)/26 **
 * c) tan (90˚-β) = cot β= 1/5 **
 * d) 1 + cot²β = csc²β **
 * 1 + (1/25) = csc²β **
 * ±(√26)/5 = cscβ **

I got the same answers! Yay! Checked by Emily Johnson

Done by Ellen Barth

I got the same thing! Good job. -Checked by Rachel West

38. (cscΘ + cotΘ)(cscΘ – cotΘ) = 1 csc²Θ – cotΘcscΘ + cotΘcscΘ - cot²Θ = 1 csc²Θ – cot²Θ = 1 1/sin²Θ – cos²Θ/sin²Θ = 1 (1 – cos²Θ)/sin²Θ = 1

because sin²Θ + cos²Θ = 1, then 1 – cos²Θ = sin²Θ

sin²Θ/sin²Θ = 1

1 = 1

40. (tanΘ + cotΘ)/tanΘ = csc²Θ (tanΘ/tanΘ) + (cotΘ/tanΘ) = csc²Θ 1 + (cotΘ/tanΘ) = csc²Θ

1 + (cotΘ/(1/cotΘ)) = csc²Θ

1 + cot²Θ = csc²Θ

1 + cot²Θ = csc²Θ

csc²Θ = csc²Θ

Done by Jonathan Eichelberger i got the same answers.-Alex Dubois

42. (a) tan 18.5 degrees = -0.3645 (b) cot 71.5 degrees = -1.0593
 * CORRECTION: your calculator must be in "degrees" to solve this problem. **
 * tan 18.5 degrees=0.335 **
 * cot 71.5 degrees=0.335 **

48. (a) cos theta = root 2/2 = 45 degrees = pi/4 (b) tan theta) = 1 = 45 degrees= pi/4 Done by: Morgan Miller

I got the same answers! Checked by: Emma McRae


 * 50- a) tan ѳ = the square root of 3; I knew that because tan ѳ also = sinѳ/cosѳ that i could assume that sinѳ/cosѳ = root 3/ 1. To find a coordinate on the map that is equivalent to this, I divided the top and bottom by two, making it root 3/2 over 1/2. This makes the coordinate (1/2, root 3/2) and the cos of this coordinate is 60 degrees**
 * b) cos ѳ= 1/2. I knew cosѳ also equals adj/hyp, so i made a triangle and found the opp to be 1. Using the identity cosѳ= tanѳ/sinѳ (i reversed the original identity), i found out that cosѳ= root 3/2. With cos being the x value, I was then able to assume that ѳ was equal to 30 degrees**


 * 52- a) cot ѳ= root 3/3; I knew that cotѳ was equal to cosѳ/sinѳ so i flipped it to where tan****ѳ****= sin****ѳ/ cos****ѳ, or 3/root3. I then eliminated the square root from the denominator, making sin****ѳ/cos****ѳ = root 3/ 1. To make this into an (x,y) coordinate I divided the top and bottom by two making it become the coordinate (1/2, rt 3/2) which is equal to 60 degrees.**
 * b) sec** **ѳ= root 2; I switched the identity sec****ѳ= hyp/adj to cos****ѳ= adj/hyp. I then knew that cos** **ѳ = root 2/2 which = to the x coordinate of the (x,y) for** **ѳ on the circle. I was able to assume then that** **ѳ was equal to 45 degrees**

I got the same answers! Checked by: Leslie Bake
 * Done by: Blake Schreiber**