6.1+due+11-9

5. Done by Mady Smith I got all those anwsers! I rounded only 2 places because thats how the book does it but this works too! Good job! Checked By: Alyssa Sturgis 6. Done by Jonathan Eichelberger
 * *** YOU ALWAYS NEED TO ROUND TO # DECIMAL PLACES*** **

Done by Andrew Kim
 * 7
 * # 7 CORRECTION: **



sorry it's slanted, done by Ben jennette

Hey Ben, Im not completely sure where your error occurred (it may have been when you wrote out your law of sins you forgot the sin in front of the angle c) but this is what i got:
 * 1) 8 Checked by Emily Johnson

15 wasn't up yet so I put up my work. - Clarissa Rodriguez


 * 16

Done By: Leslie Baker

I did it like this 125/sin(110)=200/sin(B) 200sin(110)=125sin(B) (200sin(110))/125=sin(B) 1.504=sin (B) (my sin(B) didn't =125 but got the same solution) sin(B)>1, so no solution -Daniel Leeper

I'm supposed to check 17, but it's not up yet, so this is what I did. 18/Sin(76) = 20/Sin(B) = c/Sin(C) Sin(B)= [20Sin(76)]/18 = 1.078 Sin(B) > 1, therefore there is no solution. checked by Morgan Miller.


 * 18

Done by: Courtney Venable Your work is excellent, however try not to round when you don't have to and leave the numbers in the calculator. I got slightly different: B=36.820degrees, C=67.180degrees, c=32.298. Checked by Jan Dudek

19. Done by Will Duffy hey "a" is actually 11.4 not 4.5 so there are actually 2 solutions. B1 I got 72.21 degrees B2 107.79 degrees. C1 49.79 degrees C2 14.21 degrees. c1 10.27 and c2 3.3. Checked by Cameron Johnson
 * # 19 CORRECTION: **


 * 1) 20 Done by kristen hanslik

20) a=4.5 in the book so i got sinB= 2.412 so it is no solution Peter Radecki

21. C=110 degrees, a=6, b=10 Area = 1/2ab(sinC) =1/2 (6)(10) (sin110) =30(sin110) =30(.93969) =28.191 sq.units
 * 1) 21. done by Kelsey Harmon

I got the same thing. Checked by Michael MacCrory

22. Done by Ellen Barth

Superb job Ellen. I got the same answer Checked by Miles Hennington

29) I was supposed to check this but no one put it up so i will just put up what i got

done by: Emma McRae

33.

that's what i did! checked by Alyssa Johnson
 * 1) 33 done by Amy Finkelstein

39. False. In order to solve an oblique triangle you must be given a side and then any to other parts of the triangle (either two more sides, two angles, a side and an angle, etc.) Done by Jennifer Hassell

41. True. The Law of Sines can be used in any given triangle, including right triangles. But this type of triangle can be solved in a much simpler way. For this problem, in which B=50**°, C=**90**°**, and side a=10, you can say that tan50**°** is equal to the opposite side (x) over the adjacent, 10. You can then proceed to solve for y, knowing that x^2 + 10^2 = y^2 due to the Pythagorean theorem. Work and Check by Blake Schreiber

42. Done by Matt Milan

I got pretty much the same things, although the numbers were only slightly different,I'm assuming that that was just the result of the fact that there were multiple possibilities? checked by Joon Baek