5.1+due+9-29

2. Cos theta : 2. Tan theta: sqrt 3/ 3

Sin theta: 1/2 Cot theta: sqrt 3 Cos: sqrt 3/ 2 Sec: 2 sqrt 3/ 3

I drew a rt triangle in quadrant 1 with a hypotenuse of 2, an adjacent side of sqrt 3 and an opposite side of 1 to get my answers.

Done by Kelsey Harmon Not sure if I was supposed to check this one, but I got the same answers CB: Fred Jordan

On #10 i got almost the same answers except i simplified sqrt24 so i got tan: sqrt6/12 sec: 5sqrt6/12 cot: 2sqrt6 cos: 2sqrt6/5
 * 10

Checked by Alyssa Johnson

cos^2x(sec^2x-1) cos^2x(tan^2x) (cos^2x)(sin^2x/cos^2x) final answer: c) sin^2x done by: Kristen Hanslik
 * 22

I got the same answer Miles Hennington

Done by: Jennifer Hassell

Done by: Emma McRae
 * 34

Got the same work and answer. Checked by Aggie Tutia.


 * 42.

1+csc theta / (cot theta+cos theta) =sec theta

1+csc theta / ( (cos theta/sin theta) + cos theta) =sec theta find the gcf: cos theta

1+csc theta / (cos theta ( 1/sin +1)) = sec theta

1+csc theta / (cos theta (csc theta +1)) = sec theta

1 / cos theta = sec theta

sec theta=sec theta

Done by: Frances Dannenbrink I got the same answers sec =Sec! checked by: Daniel Pugliano       46. Cos theta sec theta - cos^2 theta= sin^2 theta  ( cos theta)(1/cos theta) - cos^2 theta= sin^2   1-cos^2 theta = sin^2 theta   sin^2 theta = sin^2 theta    Done By: Anjelica Rivas ( I think I was supposed to check this one but it wasn't posted so I just did it) Tan theta / ( 1 + Sec theta ) + ( 1 + Sec theta ) / Tan theta = 2csc
 * #42 **
 * 48

cos x (Sin/cos) / cos x (1 + 1/cos) + cos x ( 1 + 1/cos) / cos x (sin/cos) = 2csc

sin / (cos+1) + (cos+1) / sin = 2csc

sin^2 / sin(cos+1) + (cos+1)^2 / sin(cos+1) = 2csc

(sin^2 + cos^2) + 2cos +1 / sin(cos +1) = 2csc

2cos + 2 / sin(cos +1) = 2csc

2(cos + 1) / sin(cos +1) =2csc

2 / sin = 2csc

2csc = 2csc

done by Matt Bogaert
 * #48 **

sec^2 x tan^2 x + sec^2 x sec^2 x (sec^2 x) = sec^4x
 * 1) 52.

Done by Blake Schreiber

I got the same thing. Great job Blake! Checked by Emily Johnson


 * 56.

done by joon baek
 * #56 **

Done by: Courtney Venable
 * 60

(you can group them)
 * 60**
 * (sec^3x - sec^2x)( - secx +1 )**
 * sec^2x (secx-1) -1 (secx-1)**
 * (sec^2x-1)(secx-1) (sec^2x -1=tan^2x)**
 * (tan^2x)(secx-1)**
 * Checked by: Leslie Baker**
 * I leave for dance and don't get home until 9:45**
 * that would make me not able to check this in time.**
 * so since it wasn't done right now this is my checking**
 * a lot of detail!!**

(cot x **+ csc x)(cot x - csc x)**
 * 62
 * cot^2 x - csc^2 x**
 * which equals -1**
 * Done by Sung Yoo**
 * 66

Thats what i got :D Checked by Emma Ross

70. Done by Will Duffy