2.7+&+Partial+Fractions+due+3-30

done by: Brooke Wiggins

Section 1 # 1


 * 1) 1 done by: Frances Dannenbrink

I got the same thing
 * 1) 1 checked by Emma McRae

Section 1 #4) Done by matt milan :P

I got the same answers! Checked by Jennifer Hassell

5) -4/x + 1/(x-1) + 2/(x-1)^2 + 3/(x-1)^3 done by Matt Bogaert

I got the same thang -Justin Ivins

6) (-5x^2-16x+1)/(6x^3+x^2-10x+3)

1 6 1 -10 3 -3/2 6 7 -3 __0 6 7 -3__ __0 -9 3__  6 7 -3 0 6 -2 0  (x-1) (x+1.5) (6x-2) A) (-5x^2-16x+1)__/__6x^3+x^2-10x+3 = ___A___ + _B_+ ___C___ (x-1) (x+3/2) (6x-2)

__B)__ -5x^2-16x+1= (x+ 2/3)(6x-2)A + (x-1)(6x-2)B + (x-1)(x+2/3)C

__C)__ x=1 -5-16+1= (5/2)(4)A -20 = (20/2)a -20 = 10A -2=A X=(-3/2) (-45/4)+ (48/2)+ (4/4)= (-5/2)(-11)B (-45/4)+ (96/4)+ (4/4)= (55/2)B (55/4)=(55/2)B (110/220)= (1/2)B B= (1/2__)__ X=(1/3) (-5/9)-(16/3)+ (9/9)= (-1/3)(1/3+3/2)C (-5/9)-(48/9)+ (9/9)= (-1/3)(2/6+9/6)C (-44/9)=(-1/3)(11/6) (-44/9)= (-11/18)C (-44/9)(-18/11)= C (792/99)=C 8=C

__D)__ __-5x^2-16x+1__ = __-2__ __+__ (1/2) __+__ __8___ __6x^3+x^2-10x+3 (x-1) (x+3/2) (6x-2)__

__-2/(x-1) + (1/2)/(x+3/2) + 8/(6x-2)__

__done by Peter Radecki__

__I found the same answer.__ __Checked by Sam Bennack.__

__Section II__ __1.__ __ ﻿ -Heather Henry(the vertical asymptote should be positive on the graph. I messed up)__

__I agree. Mady Smith__

__#2.__ __Done by Ellen Barth__ __I agree with Ellen Checked by Blake Schreiber__

__Section II #3__ __Section II #3 done by Kamryn Richard__

__That's what I got! - Clarissa Rodriguez__

__3)__ __Factor denominator to 6/ (x-1)(x+1)(X+2)__ __6/ (x-1)(x+1)(X+2)= A/ (X+2) + B/(X-1) + C/(X+1)__ __A(x+1)(X-1) + B(X+2)(X+1) + C(X+2)(X-1)__ __Plug in X=-1...6=-2C C=-3__ __Plug in X=1...6=6B B=1__ __Pug in X=-2....6=-3a A=-2__ __6/ (x-1)(x+1)(X+2)= (-2/X+2) + (1/X-1) + (-3/X+1)__ __Done By Daniel Puglinao__



__II) Number 4 done by Amy Finkelstein__ __I got the same thing__ __Checked By: Alyssa Johnson__

__#60__ __Done by: Abby Deminano__ When i factored the denominator i got (x+3)(x+1). my final answer was (x-2)/(x^2+4x+3)=[(5/2)/(x+3)]+[(-3/2)/(x+1)] Will Duffy

__66.__ __#66. done by Kelsey Harmon__ I got the same answers for A and C, but for B, I got -1. On the left hand side, you had (-1)^2-(-1)+2=1+1+2=4. Everything else though, is right on target. Checked by Aggie Tutia __done by: Valerie Finstad__

__I concluded with the same answer. Quinn Taylor__

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