4.5+(day+2)+due+9-17



Done by Jose Castellanos

2) Correct. I got the same answer. 4) Correct. I got the same answer. 6) Correct. I got the same answer. Checked By: Frances Dannenbrink

8,10,12

Done by: Julia Hoagland-Sorensen

8) Correct, got the same answer 10)Correct, got the same answer 12)Correct, got the same answer Checked Fortunato De La Puente

14,20 14) Y= 3/4 cos pi/12 x Y=-a cos b (x+-c) +-d amp= 3/4 2pi/b = period 2pi/(pi/12) 2pi times 12/pi= 24 Period= 24

20. f(x)= sin x g(x)= -1/2 sin x g(x) and f(x) have the same periods and shifts but g(x) has an amplitude of 1/2 and it is flipped over the x-axis So g(x) will be a thinner graph than f(x) and its will be flipped Done by Cameron Johnson

For #14 I got the same thing! awesome, good job! For #20 I literally wrote that exactly! nice man!

Checked by Cameron Johnson

22) **f(x) = cos4x**
 * 22, 24
 * Has a Amplitude = 0
 * Not Reflected
 * Period of pi/2 (2pi/4)
 * No Horizontal Shift
 * No Vertical Shift

For f(x)=cos4x I got the same answers! For g(x)=-6+cos4x I got: amp:1 Not reflected Period:2pi/4 Shifted down 6 units Checked by:Valeria Chelala 24) **Graph F** has a period of 2pi and its hard to read the period for **Graph G** but we know that it has a horizontal compression so its period is smaller than Graph F. They both have amplitudes of 1 and Graph F doesn't appear to have a shift but its hard to see for Graph G. I got the same answer! Checked by:Valeria Chelala
 * g(x) = -6 + cos4x**
 * Amplitude = 6
 * Is Reflected
 * Has a period of 4 (2pi/4)
 * No Horizontal Shift
 * No Vertical Shift

Done by: Courtney Venable



Done by: Rebekah Adair 26. I noticed the same similarities and differences between the graphs. 40. For my graph I used a 2pi period as well, but on my graph I refelected the cosine smile face across the y axis to show two full periods. Checked by Kelsey Harmon
 * 42

Posted by Emily Johnson done by: Alyssa Johnson

Looks correct Miles Hennington

done by joon baek
 * 44

44) I got the same amplitude of 10, reflection, and a period of 12, but on my graph looked different. (you might have just labeled your x- axis wrong on your graph) because it is a period of 12, my first point was located at 0 on the x-axis and -10 on the y-axis, my second point was located at on 3-on the x-axis 0-on the y-axis, the third point would be at 6-on the x-axis and 10-on the y-axis, and the fourth point was located at 9 on the x-axis and 0 on the y-axis, and my fifth point was located at 12 on the x-axis and negative ten on the y-axis Checked by: Kamryn Richard
 * #44 CORRECTION: **


 * 50

done by Anjelica Rivas

I got the same information and the same graph. Checked by Kristen Hanslik


 * 52

... I am supposed to check 52 (unless I wrote down the wrong number) but the work wasn't uploaded, so here is my "check" work: Checked by: Abby Demiano

**#54 CORRECTION:**

Done by: Clarissa Rodriguez

Looks good I got the same for the amplitude and the period. Checked by: Michael MacCrory

d = -4 d = - 4.5 Done by Sung Yoo 64. It's cosine, not sin so i got a=-2, i got the same thing for d. 66. I got the same thing. Will Duffy **#64 CORRECTION:** **y = - 1 cos x - 3** ** **#66 CORRECTION:** ** ** **y = - 1/2 cosx - 4** **
 * 1) 64 a = 1 Equation = y = cos x - 4
 * 1) 66 a = 1 Equation = y = cos x - 4.5

Worked by: Emma Ross I got the same thing, although i am not 100% sure, i have been a bit confused on the periods-Alex Dubois **#70 CORRECTION:** **y = 2 sin 3 (x + pi/4)**

For A I typed the equation into my calculator. That's the graph I got on the right. For B I just used the maximum and minimum functions to figure out the lowest month and the highest month. I just used the numbers 1-12 because there is 12 months in the year and then whichever had the highest which was the 12th month, December was the maxiumum and whichever one had the lowest, which was 6th month, June. Worked by Meredith Hohl
 * 74

Done by Jonathan Eichelberger Check by Jan Dudek: I got the same answer! :)


 * 81, 82 and 83

81. True. b=3x/10 2pi/3x/10= 2pi/1=10/3x - to divide, you have to multiply by the reciporcal this gives you 20pi/3

82. False. y=1/2cos2x in this one the amplitude = 1/2 the other one- y= cosx in this one the amplitude = 1/2 is not twice as big as 1

83. False. y=-cosx: this graph is reflected so it will be a frown face, the highest point being at the top, and the other graph is a non reflected sine graph which means it starts by going up, its highest point being at the top as well. These two graphs are not reflected, they are on the same line.

Worked by Alyssa Sturgis

81. Correct. I got the same answer. 82. Correct. I got the same answer. 83. I got false as well, but the help from the back of the book said the answer is true, so I was confused. Why I got the answer to be false was... in my drawing of y = -cosx, the graph is reflected like Alyssa said. The first point on a normal cos graph is the highest point, so reflected it would be the lowest point at (0, -1), then at pi/2, the second point would be on the middle line, then the highest, back to middle, and then back to the lowest, so it does make a frown face. For the second y=sin(x + pi/2), the graph has a horizontal shift left pi/2. The sin graph starts on the x axis, the middle, then goes to the high point 1, then the middle, then the low point, -1 and then back to the middle. So, as Alyssa said, they are on the same line.... a little confused about this.. Checked by Mady Smith

**#83 CORRECTION:** **TRUE see graph below**