2.2+due+3-3

1-8) 1-8 done by Emma McRae, sorry it took so long my computer wasn't letting me upload the picture

10. Posted by Sam Bennack.

14. plug in y1 = -1/3(x^3 - 3x +2) plug in y2 = -1/3x^3

18. f(x) = 1/3x^3 + 5x leading coefficient: positive power: odd graph falls to the left and rises to the right (left: down) (right: up) Done by Mady Smith I agree, good job. Checked by Freddie Jordan

I was supposed to check 20,22,24 but they're not here so this is what I got 20. Left:up right:down 22.left: up right:up 24. Left: down right:down

26.-1(x^2-49) (X-7)(X+7) Zero's are 7 and -7 both multiplicity of 1 28.(X^2+10X+25) (x+5)^2 Zero is -5 (multiplicity 2) 32.X^4-X^3-20X^2 X^2(X^2-X-20) X^2(X-5)(X+4) Zero's are 0 multiplicity 2, 5 multiplicity 1, and 4 multiplicity 1 Done by parker tennet

Looks good, I got the same answers checked by Jose Castellanos

34. x= (2/5) mult 1 and -2 mult 1

38. y= (1/4)x^3(x+3)(x-3) x=0 mult 3 x=3 mult 1

40. g(t) = t^5 - 6t^3 + 9t t(t^4 - 6t^2 +9) t(t^2 - 3)(t^2 - 3) t=0 mult 1 t=sqrt(3) mult 2 t= - sqrt(3) mult 2

Done by Jennifer Hassell

34) you just left out a 4 under the sqrt but its correct 38) i also got a x=-3 also and 40) is correct Peter Radecki

46 & 50

Sorry I can't figure out how to turn it! I got the same answers! Daniel Pugliano
 * 1) 46 and #50 done by Frances Dannenbrink

66 and 67 done by Blake Schreiber

Thats what I got - Daniel Leeper

68 & 70 by Meredith Hohl

i agree with 70 -brooke wiggins
 * 1) 68 i got x=4 and x=-4 both mult=1... so for the zeros at 4 and -4 the line would go through the points

74 & 76 done by Miles Hennington I got the same answer Checked by: Andrew Kim

86 and 64 done by Preston Wall For 86, I got all real numbers for the domain and my graph and the graph should look like this: Everything else is righty-o! xoxo Aggie Tutia!

I got the same thing! checked by: Alyssa Johnson
 * 1) 78 and 80 done by: Amy Finkelstein